These include the power generation of a solar panel, the energy storage of an accumulator, the length of a day, and the length of a night. The optimal ratio of accumulators per solar panel relies on many values in the game. This is taken from Accumulator / Solar Panel Ratio (which calculates this in an impressive mathematical way!) and another post in that thread (which calculates the solar panel to megawatt ratio in a different way).Ī small 9x9 setup demonstrating the 20:24 "close enough" ratio above. This means that you need 1.428 MW of production (of solar panels) and 100MJ of storage to provide 1 MW of power over one day-night cycle.Ī "close enough" ratio is 20:24:1 accumulators to solar panels to megawatts required (for example, a factory requiring 10 MW can be approximately entirely powered, day and night, by 200 accumulators and 240 solar panels - this approximation differs from optimal only in that it calls for 20 extra solar panels, which is negligible but remember that the difference between the "close enough" ratio and the optimal ratio increases as you add more solar panels). The optimal ratio is 0.84 (21:25) accumulators per solar panel, and 23.8 solar panels per megawatt required by your factory (this ratio accounts for solar panels needed to charge the accumulators). It could be stretched 50 underground pipes far away without need of aditional pumping.A possible setup Solar panels and accumulators Optimal ratio So when you split the stream by T cross, it works.Ĥ leaf plant 48 heaters is suported by 6 offshore pump and 2 electric pump and 2 storage tanks. It accept feeding three pipes into one storage 3 times faster, as fallow up one pump can suck out water from storage by a speed up to 12000. It sound a wierd, but flow system is playfull. It is enough to feed water for 2x12 heaters. Close to heaters, 3 pipes goes into one storage tank, then aattached one pump out to the "T" type cross pipe. Pipes begin with 3 offfshore pump, fallow 3 paralel pipes about 16 tiles of pipes (underground) to the heaters. 3 pipes per 24 heaters allows quite long transfer without further pumping. In my design (smaller) four leaf nuclear I am using 3 pipes for each 24 heaters. With high truthput on the edge of capacity you might see fluctuations. I have pumps after 5 underground pipes, equivalent to 10 pipes, which I thought should be more than enough to keep the water flowing. Also according to the wiki, water flow capacity drops to 1200/sec at 17 pipes. That is the ratio I have for my reactors. putting in a complete second line from off-shore pump to heat exchangers with a pump every 5 underground pipes.Īny experiences/suggestions/comments are welcome.ġ2 heat exchangers to 20 steam turbines. putting in more pumps, say one pump for every underground pipe adding a second off-shore pump to start off with twice as much water (in theory) I am going to experiment with a few options today and I will report on the results: So even though I have a total of 1700 steam turbines, for a theoretical max output of 9.89GW, in practice it only produces 66/103 of that, so I start running out of power for my base around 6.3GW. Slowly the pipes and heat exchangers refill with water. One by one, from furthest away to closest, the heat exchangers top working 'no fuel'. Once the nuclear fuel cell is consumed, the heat pipes slowly cool down (I have delay on refueling until steam drops to a certain level). One by one, they drop to 66/103 steam per second. As water is consumed to produce steam, the water supply drops until the heat exchangers one by one stop producing the full amount of steam because they are out of water. For a few seconds after the 12th exchanger starts operating, steam production is in full swing (103/103 steam output). As the reactor produces heat, the heat pipes and heat exchangers increase in temperature and one by one, from closest to the reactor to furthest away, the heat exchangers start producing steam. To start, the water pipes and heat exchangers are full of water the heat pipes are cool and the exchangers are not operating 'no fuel'. So I spent some time watching one of my reactors operating, and observed the following: I ran low on power yesterday, and threw in another reactor complex to compensate. In theory, there is no difference between theory and practice.
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